Local-energy measurement verification 2026-10-06
Uniformly sample one positive local term and measure the effect . The averaged energy-flag effect on a witness is , where is the number of terms. Repetition with a threshold halfway between the promised flag probabilities uses witness registers for constant error. A spectral tensor-product analysis, as in QMA parallel repetition with entangled witnesses, proves soundness against entangled witnesses. Constant-locality positive operator-valued measures are efficiently implementable using one ancilla qubit.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 67 3 b Solution Created 2026-10-03 Updated 2026-10-06
Interpret the high-success formulation as completeness at least and soundness at most , where for a growing polynomial . This is the standard error-reduction claim. Literally placing around a success probability approaching one supplies no useful lower bound; it is the failure probability that must be inverse-polynomially small.
Let be the quantum verifier acceptance operator acting on one witness register:Acceptance on is . On a NO instance, ; on a YES instance, an honest witness has acceptance at least .
Ask for witness registers, with odd, run independently on each register with fresh ancillas, and accept a strict majority. The QMA parallel repetition with entangled witnesses acceptance operator isDiagonalize . In the tensor-product eigenbasis, an eigenvalue of is the majority probability for independent Bernoulli random variables with parameters equal to the selected eigenvalues of . On a NO instance every parameter is at most . Coupling these variables using independent uniform random numbers shows that their upper majority tail is bounded by the tail with every parameter . This bounds the operator norm and therefore covers every supplied witness, including a witness entangled across the registers. No independence assumption about a dishonest witness is being made.
For a valid Chernoff bound, if is a sum of independent Bernoulli variables of parameter at most , Markov's inequality applied to yieldsAn honest product witness on a YES instance gives independent trials with rejection probability at most , so its failure probability has the same bound. The printed concentration bound is not valid as stated: for five trials at parameter , the upper-majority probability is . The valid bound above suffices for a rigorous proof.
Choose the next odd integer above . ThenThe witness length and circuit size increase by only ; the majority calculation has polynomial overhead. Conversely, inverse-polynomial failure probability is at most for all sufficiently large input lengths. Finitely many smaller lengths can be handled by hard-wired verifiers, giving the usual constants. Hence the two definitions give the same class QMA. The same QMA error reduction argument also yields exponentially small failure with polynomially many copies.
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 67 3 d Solution Created 2026-10-03 Updated 2026-10-06
Use an -qubit state as the witness. Uniformly choose a term and perform the two-outcome positive operator-valued measure . Regard the second outcome as an energy flag. For witness , its probability isThis is an efficient local-energy measurement verification: a unitary operator on the relevant qubits and one ancilla qubit can implement the measurement using the isometryThe local dimension is constant; the term matrices and the measurement can be approximated to inverse-polynomial accuracy. Uniform choice of and the classical threshold comparison also have polynomial overhead.
SetIn the nontrivial case , is inverse-polynomial. Cases outside this energy range are decided directly from .
Ask for witness registers, measure an independently sampled local term on each, and accept if the mean number of energy flags is at most . An honest product ground state on a YES instance has flag probability at most . The Hoeffding inequality gives failure at most . For completeness, the required Bernoulli concentration estimate follows by bounding the centered log moment-generating function : and is a tilted Bernoulli variance, at most . Hence ; exponential Markov's inequality optimized at yields , and the lower-tail version follows in the same way.
Soundness must also cover entangled witness registers. The averaged flag effect is . All its eigenvalues are at least on a NO instance. The repeated verifier's acceptance effect is a polynomial in the commuting tensor-factor operators and . In their product eigenbasis its eigenvalues are lower-tail probabilities of independent Bernoulli variables whose parameters are each at least . Their lower tail is bounded by the identical-parameter tail at , using the same uniform-variable coupling as in QMA parallel repetition with entangled witnesses. Therefore its operator norm is at most , which bounds acceptance for any entangled witness.
Choosinggives completeness at least and soundness at most . A slightly larger constant absorbs implementation errors; for example, approximate each flag effect in norm to at most , retain a gap at least , and increase by a constant factor. The total witness length and circuit size are polynomial. Thus
QMA error reduction 2026-10-06
Starting from completeness and soundness , run an odd number of parallel copies and take majority. The QMA parallel repetition with entangled witnesses argument proves soundness for arbitrary repeated witnesses. Exponential Markov's inequality gives majority error at most . Hence copies suffice for error , with polynomial overhead when the target error is inverse-polynomial or exponentially small in input length.