Consider a one-step stencil with new-level coefficients , and at offsets , and old-level coefficients , at offsets . For , its exact-solution residual starts at fourth degree with coefficient . Thus its normalized local truncation error is third order at fixed nonzero Courant number, except at the exact-shift values ; zero gives the zero-step identity. For its Fourier symbol, . Uniformly invertible stable steps occur for , or .
Articles by others on the same topic
There are currently no matching articles.