Past exam of the mathematics course of the University of Cambridge 2007 iii Paper 23 6 Solution Created 2026-10-03 Updated 2026-10-14
Here is algebraically closed and is a connected smooth projective curve. For a scheme over , let . The degree- Picard functor of a curve assignsOne can equivalently take the associated faithfully flat sheaf. It is essential to divide out by line bundles from the base: a parameter space should remember the family on , not an independent base line bundle.
Choose . A class can be normalized as , with its canonical trivialization along . Since , an automorphism of a line bundle is multiplication by a base unit, and preserving this normalization forces that unit to be . Descent of line bundles is effective, so normalized bundles satisfy the faithfully flat sheaf condition with no automorphism ambiguity. Thus this normalized description works on families, including nonreduced bases, rather than only on -points.
We construct a representing scheme by Picard charts from nonspecial divisors. Fix and put . The symmetric product of a curve represents relative effective Cartier divisors on a curve of degree and has a universal divisor . This uses the scheme symmetric product, not the naive set of unordered -points. Locally on a smooth curve, a divisor of length is described by a monic polynomial in a smooth coordinate; its coefficients are elementary symmetric functions, so this construction includes coincident points in any characteristic. These local descriptions give the usual effective-divisor interpretation of the symmetric product.
Let be the open set where . It is open by semicontinuity theorem for coherent cohomology. The Riemann-Roch theorem gives there, so is the unique effective divisor in its line-bundle class. For every fixed effective divisor of degree , take a copy of , with familyof degree . Normalize it along as above.
This chart represents the open subfunctor defined byIndeed, for a family satisfying that condition, cohomology and base change for line bundles on a curve makes a line bundle on , with formation commuting with base change. The rank is one by Riemann-Roch theorem. The evaluation mapis a nonzero section on each fibre, up to the base twist. Its zero scheme is a relative effective Cartier divisor on a curve of degree . To check the family assertion, source and target are flat over and the fibre maps are injections of line bundles on an integral curve, so their cokernel is flat over . Their zeros are Cartier, and the zero scheme is proper with finite fibres of length , hence finite flat of degree . It therefore defines a unique map . Conversely this construction recovers the family modulo a base line bundle.
The base-change step controls infinitesimal families as well. Locally, a finite free complex computes the two cohomology groups. Vanishing of its degree-one cokernel on fibres makes the last differential surjective by the Nakayama lemma. Splitting that differential leaves a locally free degree-zero kernel of rank one and commutes with base change. This is the standard finite-complex form of the permitted cohomology semicontinuity and base-change results.
These chart subfunctors cover all degree- families. For a geometric-fibre line bundle of degree , the preceding solution gives and . Choose points successively so that each imposes one independent condition on the current section space. At each stage that space is nonzero; a nonzero section has finitely many zeros, so a point outside its zero set can be chosen, also outside the finitely many previously chosen points. For their sum ,and Riemann-Roch theorem forces . The points may be chosen in even when the fibre field extends , since is infinite and a nonzero section on the base-changed curve has only finitely many zeros. Thus fixed divisors defined over suffice. Upper semicontinuity gives an open neighbourhood on the base for each successful .
It remains to glue the charts explicitly. On , the locusis open. The line bundle inside the braces has degree ; its unique section up to scale has an effective zero divisor . Base change and the evaluation construction make a morphism . It satisfies . Reversing gives its inverse. On triple overlaps the transition maps compose correctly because the residual effective divisor is unique. Hence the copies glue along these open isomorphisms to a scheme .
The normalized bundles glue as well: on overlaps their normalized isomorphisms exist and are unique, so they satisfy the cocycle condition. Let denote the resulting universal normalized line bundle on . For any , the open cover where the conditions for some hold gives compatible maps , and thus a unique map . Pulling back reverses this procedure. We have established a natural bijectionThis proves representability of the full functor, not just a parametrization of individual line bundles. The nonspecial-divisor construction is also recorded in Stacks Project, Picard scheme of a curve.
Finally tensoring by is a natural isomorphism for every integer . Transporting the universal bundle back constructs its degree- representative , usually denoted . Thus every degree component is represented. These identifications depend on the chosen point and twist; intrinsically the degree-zero component is a group scheme and each degree component is its torsor.
Past exam of the mathematics course of the University of Cambridge 2009 iii Paper 18 1 Solution Created 2026-10-03 Updated 2026-10-14
Throughout the algebraic questions, is a smooth projective connected algebraic curve over the algebraically closed field . This is the curve convention needed for the Jacobian variety; for an arbitrary singular or nonproper curve the assertions need not hold. Choose and write .
The degree- Picard functor of a curve iswith pullback as its action on morphisms. Equivalently, normalize by tensoring with and remember the resulting trivialization along . Since , an automorphism of a line bundle is multiplication by a base unit; preservation of this trivialization forces that unit to be . Thus normalized line bundles have effective descent and the displayed functor is already the appropriate sheaf, rather than just a list of classes over fields.
Here is a construction of its representing scheme. The symmetric product of a curve represents relative effective degree- Cartier divisors. It is projective, and its completed local ring at is a power-series ring in the elementary symmetric coefficients of local parameters at each . Thus it is smooth of dimension , in every characteristic. PutThis is open by the semicontinuity theorem for coherent cohomology. It is nonempty: choose points successively imposing independent vanishing conditions on , so that , and use Serre duality. The Riemann-Roch theorem gives on .
For any fixed line bundle of degree , use a copy of with the universal normalized line bundle . This represents exactly the open subfunctor on which . Indeed, cohomology and base change for line bundles on a curve makes a rank-one vector bundle. The evaluation morphismhas a unique relative zero Cartier divisor of degree and recovers the point of . No choice of a global generator on is needed. Conversely that zero Cartier divisor recovers modulo a bundle from .
These charts cover: given any degree- line bundle , choose a nonspecial effective degree- Cartier divisor and take . On the overlap of and , the unique effective representative of is constructed by the same rank-one evaluation map. It therefore gives a regular transition morphism; uniqueness gives both the inverse and the cocycle identity. Gluing gives a scheme representing , with a universal normalized line bundle.
The construction is of finite type, not an infinite union of indispensable charts. Choose and a fixed line bundle of degree . Every has a nonzero section by the Riemann-Roch theorem, so the universal effective Cartier divisor gives a surjection . The inverse images of the charts cover the projective, hence quasi-compact, symmetric product of a curve . A finite subcover gives finitely many charts for . This surjection also makes irreducible. The charts show that it is smooth of dimension .
For properness, apply the valuative criterion for properness. Let be a discrete valuation -algebra with fraction field , and let be a degree- line bundle on . A rational section represents it by a Cartier divisor. Its closure in the regular surface is again a Cartier divisor, since regular local rings are factorial. Thus extends to a line bundle on , whose fibre degree remains by constancy of line bundle degree in a family. Two extensions with the same generic class differ by a vertical Cartier divisor. The special fibre is irreducible, so that Cartier divisor is an integer multiple of the entire fibre, the principal Cartier divisor of a power of a uniformizer. The extensions therefore give the same normalized Picard class. This proves existence and uniqueness in the valuative criterion, hence separatedness and properness of the finite-type scheme .
Consequently is a smooth proper -variety of dimension . Tensoring by identifies it with . On the tensor product and inverse of line bundles induce the algebraic group operations; it is the Jacobian variety, an abelian variety.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 18 4 i Solution Created 2026-10-03 Updated 2026-10-14
For a line bundle on , put , and choose an ample line bundle on . Fix . For sufficiently large , both and vanish, by Serre duality and negativity of the degrees of their dual canonical twists. The semicontinuity theorem for coherent cohomology makes both groups vanish on a neighborhood of . The family is flat over : is flat and the sheaves in question are locally free.
On that neighborhood the Riemann-Roch theorem givesUpper semicontinuity of both zeroth sheaf cohomology dimensions, after shrinking again, gives and . Hence . The degree is locally constant, and thus constant on connected . With the usual convention that a variety is irreducible, this proves the assertion as printed. If disconnected varieties are allowed, the necessary qualification is constancy on each connected component: take to be two points and the bundles and to see that a global constant degree need not exist.
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 126 2 i b Solution Created 2026-09-24 Updated 2026-10-14
Use the same finite complex computing cohomology in a proper flat family. In fixed bases its differentials are matrices over . The condition that such a matrix have rank at most is closed, being defined by its minors. Sincethe condition that this dimension be at least is a finite union of intersections of closed rank loci. It is therefore closed. This is the semicontinuity theorem for coherent cohomology.