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Singular value perturbation bound (∣σj​(A)−σj​(B)∣≤∥A−B∥2​)

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Linear algebra Singular value decomposition Singular value
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For equally sized matrices, corresponding ordered singular values differ by at most the spectral norm of the perturbation. Indeed, let Bj−1​ be a best approximation of matrix rank at most j−1. The Eckart-Young-Mirsky theorem and the triangle inequality give σj​(A)≤∥A−Bj−1​∥2​≤∥A−B∥2​+σj​(B). Interchanging A,B proves the bound.

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  • Past exam of the numerical linear algebra course of the University of Oxford / 2025 / 1 / b / iii / Solution
  • Past exam of the numerical linear algebra course of the University of Oxford / 2025 / 1 / b / ii / Solution
  • Past exam of the numerical linear algebra course of the University of Oxford / 2025 / 1 / b / iv / Solution

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