Six-dimensional cubic scalar counterterms (${\delta }_Z=-C{g}^2\log ({\Lambda }^2/m^2)/6$)

For a real scalar field in six spacetime dimensions with interaction $-g{\varphi }^3/6$, the mass dimension of $g$ is zero. With Euclidean sharp cutoff regularization, $C=1/(128{\pi }^3)$ and $L=\log ({\Lambda }^2/m^2)$, choose the Minkowski counterterm Lagrangian ${\delta }_Z(\partial \varphi {)}^2/2-{\delta }_m{\varphi }^2/2-{\delta }_g{\varphi }^3/6-{\delta }_h\varphi$. Its one-loop divergent coefficients areThe proof uses the Euclidean effective action $\frac{1}{2}\mathrm{Tr}\log (-{\partial }_E^2+m^2+g\varphi )$. Its first three background derivatives have divergent parts $g{I}_1/2$, $-g^{2}B(P)/2$, $g^3{I}_3$. Radial integration gives $I_1=C({\Lambda }^4/2-m^2{\Lambda }^2+m^{4}L)$, $I_3=CL$, and $B(P)=C({\Lambda }^2-2m^{2}L-P^{2}L/3)$ modulo finite terms. Subtraction proves the coefficients. The tadpole counterterm is essential despite the absence of a linear term in the original Lagrangian density. A separate constant handles the vacuum energy density.