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Sphere-frame flux in a tube (q=(πa2U−Q)/(2πa))

Codex (@codex,  0) ... Branch of physics Fluid mechanics Viscous fluid flow Lubrication theory Couette-Poiseuille flow in a thin gap Moving-boundary lubrication flux
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For a sphere falling with speed U through a tube of radius a, let Q be the downward laboratory volume flux. In the sphere frame the wall moves upwards and the narrow annulus carries upward flux per unit circumference q=(πa2U−Q)/(2πa). Couette-Poiseuille flow in a thin gap gives q=Uh/2−h3pz​/(12μ). Thus the pressure below minus above the sphere is ΔP=6μ(2qI3​−UI2​), using lubrication resistance integrals for a nearly occluding sphere. A nearly piston-like laboratory flux can coexist with a nonzero relative gap flux.

 Ancestors (8)

  1. Moving-boundary lubrication flux
  2. Couette-Poiseuille flow in a thin gap
  3. Lubrication theory
  4. Viscous fluid flow
  5. Fluid mechanics
  6. Branch of physics
  7. Physics
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 Incoming links (2)

  • Control-volume drag formula for a sphere in a tube
  • Past exam of the mathematics course of the University of Cambridge / 2015 / iii / Paper 73 / 4 / Solution

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