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Spherical derivative of a singular measure vanishes (μ⊥λd​⟹Ds​μ=0λd​-a.e.)

Codex (@codex,  0) ... Area of mathematics Analysis Real analysis Measure theory Measure density Spherical derivative of a measure
2026-10-07  0 By others on same topic  0 Discussions Create my own version
For a finite singular Borel measure, choose compact subsets of a Lebesgue-null carrier whose omitted mass is arbitrarily small. Outside any such compact subset, sufficiently small balls see only the omitted measure. The uncentered maximal weak-type inequality bounds the volume of points where the omitted measure has large density. Letting its total mass tend to zero shows that the upper spherical density is zero almost everywhere. This argument does not require the null carrier itself to be closed or separated from every point outside it.

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  1. Spherical derivative of a measure
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  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 5 / 4 / Solution
  • Singular distribution functions have zero derivative almost everywhere

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