Past exam of the mathematics course of the University of Cambridge 2004 iii Paper 49 1 Solution Created 2026-10-03 Updated 2026-10-14
Use a mostly-plus target metric tensor and the standard open-string mode expansion convention . The integer string oscillator level is , whose eigenvalues are nonnegative integers. Then , so the string mass-shell condition givesThe ground state is a tachyon, and the level-one state is massless. The physical string state conditions in old covariant string quantization areOnly the positive-mode Virasoro constraints annihilate a ket; their negative-mode partners annihilate the corresponding bra. Imposing both signs on every ket would contradict the nonzero Virasoro central extension.
The central charge comes from normal ordering the quadratic oscillator expressions. Classically their Poisson brackets have no central term. Quantum mechanically, moving annihilation operators through creation operators produces double contractions. From the oscillator commutator one obtains , which gives the noncentral part .
The coefficient is fixed by the free-boson Virasoro central term. On a formal zero-momentum vacuum, for ,The two contraction pairings giveHere ; the time coordinate contributes one, just as each spatial coordinate does. Comparing with the Virasoro algebra provesThis counts covariant target coordinates. It is distinct from the physical transverse polarizations. Including the central charge of reparameterization ghosts gives ; cancellation of the worldsheet Weyl anomaly gives the usual critical dimension of the bosonic string .
A general level-one state isThe zero-mode constraint requires . Since , the remaining nontrivial positive-mode constraint is ; all with act trivially at this level. Thus the polarization vector is transverse to a nonzero null momentum.
There is also a null string state . It is physical when and orthogonal to every physical polarization. The null-state quotient of a string therefore identifiesChoose . Transversality sets , and the null-state identification removes this common component. The remaining spatial components have positive norm. Hence the physical level-one states form a massless vector with polarizations, or 24 at the critical dimension. The removed component is gauge redundancy. States violating the constraints, including independent timelike negative-norm polarizations, are unphysical; physical null states are removed by the quotient rather than counted as additional particles.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 306 3 Solution Created 2026-10-03 Updated 2026-10-14
Use a genus-zero Polyakov path integral, target signature and all four momenta incoming. Define the Mandelstam variables by , , . The string mass-shell condition is and momentum conservation is , soThe reduced amplitude omits the overall momentum-conservation Dirac delta distribution and any conventional overall scattering-matrix phase. Interpret each tachyon vertex operator as normal ordered; self-contractions must not be included.
The free-boson worldsheet propagator is . Wick theorem then evaluates the normal-ordered exponential correlator as the Koba-Nielsen factorThe worldsheet zero mode supplies momentum conservation. Four vertices give and the sphere contributes through the string genus expansion, leaving .
The sphere's residual Möbius transformations fix three insertion points. In sphere gauge fixing for four string vertices, take . The worldsheet ghost fields, equivalently the Faddeev-Popov determinant for this residual group, supply . At finite , this determinant grows as , while the matter correlator decays as by momentum conservation and the tachyon mass shell; their product has a finite limit. Equivalently the weight- matter operator at infinity is normalized with , while the ghost pair uses the inverse factor. After stripping the fixed-position normalization, onlyremains. Here choose the standard complex-coordinate measure . With instead, the reduced normalization must acquire a factor two to give the same requested amplitude. Absolute vertex/sphere normalization is a convention; this choice fixes it consistently with the displayed prefactor.
Set , , . Then and the integrand is . To evaluate the complex beta integral first work where . This ensures convergence near , and infinity. Set and . Schwinger parameterization givesCompleting the square, the Gaussian integral is . Change variables to and ; their Jacobian determinant is . Integrating gives . The remaining integral is the ordinary beta function . ThusRestoring and substituting the Mandelstam variables proves the Virasoro–Shapiro amplitude:For physical scattering the original position integral generally fails to converge. The formula defines the amplitude by analytic continuation from the convergence domain, with the desired scattering boundary value at real poles; the convergent integral should not be claimed valid for every physical momentum.
The Gamma function is a meromorphic function, with simple poles at nonpositive integers and no zeros, while its reciprocal is an entire function. Consequently it is a meromorphic function of the independent invariants and a crossing-symmetric scattering amplitude: permuting leaves it unchanged. Its generic channel poles areand the same tower in and . They represent the exchanged bosonic string mass spectrum: the tachyon, massless states including the graviton, and an infinite sequence of massive closed-string levels. There are no threshold branch cuts at this tree order.
A precise check of factorization is the Virasoro–Shapiro amplitude pole residue. Near , set in the nonsingular factor. The Gamma function recurrence givesCombining this with showsThe residue is a degree- polynomial in , consistent with exchange up to spin and scattering-amplitude factorization. At exceptional kinematics reciprocal Gamma zeros can remove apparent poles. In particular, when both and approach nonpositive integers, the zero from cancels the putative double pole, leaving channel simple-pole terms. Thus one must not count products of numerator poles without using .
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 306 4 Solution 2026-10-03
Insert the given closed-string mode expansion into the stress tensor and compare . Normal ordering gives
The inverse of the worldsheet Laplacian gives the free-field operator-product expansionHenceExtracting the Laurent modes by contour integration yields the string oscillator algebra
The vanishing of the worldsheet stress tensor becomes the Virasoro constraintsSince and the bosonic-string normal-ordering constant is , these zero-mode constraints are the target-space string mass-shell conditionThereforeThe positive-mode constraints further requireand null string states identify polarizations that differ by momentum-longitudinal terms. The symmetric trace-free, antisymmetric, and trace sectors of describe the graviton, Kalb–Ramond field, and dilaton, respectively.
Finally, the state–operator correspondence maps toAdding its integrated massless closed-string vertex operator to the string nonlinear sigma model changes the background coupling byThus a Fourier mode is precisely a linearized deformation of the target-space metric. Its transversality, mass-shell condition, and polarization gauge redundancy are the worldsheet statements that the deformation is marginal and is defined up to a linearized spacetime diffeomorphism.