Subdifferential under scalar affine composition ($\partial [h(c^{T}x+b)]=c\partial h(c^{T}x+b)$)

For a finite convex function $h:\mathbb{R}\to \mathbb{R}$, the function $f(x)=h(c^{T}x+b)$ is convex. The subgradient inequality gives $c\partial h(u)\subseteq \partial f(x)$, where $u=c^{T}x+b$. Conversely, every subgradient $g$ of $f$ annihilates $\ker c^T$, because $f$ is constant on lines in those directions. For $c\ne 0$, write $g=cv$ and test the subgradient inequality at $y=x+(t-u)c/\Vert c{\Vert }_2^2$; this proves $v\in \partial h(u)$. For $c=0$, $f$ is constant and both sides are $\{0\}$ since a finite convex function on the real line has a nonempty subdifferential everywhere.