Let be a complete metric space and let be nonempty closed bounded subsets with and Hausdorff distance , where and . Then is nonempty and closed, and .
To prove this, start with any and choose with . The triangle inequality makes the resulting sequence a Cauchy sequence. Its limit exists by completeness and belongs to every by nesting and closedness. Its distance from the starting point is at most . Let and take the supremum over starting points. The reverse directed distance is zero since . Unlike the usual shrinking-diameter form of Cantor's intersection theorem, the sets need not have diameters tending to zero.

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