The Cameron-Martin space of a Gaussian random variable in a Banach space is most conveniently defined using the first Gaussian chaos. Work over the real separable Banach space , with continuous dual space . For a centered Gaussian random variable in a Banach space, define
The set inside the closure is already a linear subspace. Every is a centered Gaussian random variable. The Bochner integral defining exists: Fernique's theorem states that for some , , and then Cauchy-Schwarz inequality gives .
The map is injective. Indeed, implies for all . Density of these observations in then implies . Define the Reproducing-kernel Hilbert space by
The injectivity makes the inner product unambiguous, and the completeness of makes a Hilbert space. The embedding into is continuous since
For put . The reproducing property is
This defines the Banach-space Gaussian RKHS even for a degenerate Gaussian measure.
For , write . There is a measurable coordinate on , obtained as a limit in L2 space of continuous linear observations, and has normal distribution . The Cameron-Martin theorem for a Gaussian measure, in its real separable Banach space form, states that if is the probability law of , then the probability law of is an equivalent probability measure to precisely when . For such a shift,
For the two laws are mutually singular measures. The coordinate need not be a continuous functional on , and the sample need not belong to .
Apply this theorem to the shift . With , it gives
Choose the measurable coordinate so that on a symmetric set of full -measure. This is possible by taking an almost-surely convergent subsequence of the approximating linear observations and intersecting its convergence set with its negative. Alternatively the joint law of is invariant under simultaneous negation, directly from those observations and their mean-square convergence. Since and the centered Gaussian measure is symmetric, the two exponential integrals with signs and agree. Consequently
because . The symmetric Gaussian translation lower bound is therefore
Only symmetry and Borel measurability of are required; convexity is not needed.
There is one degenerate flaw in the last printed claim. The separable Banach space with has dense in , and all positive-radius balls have probability one. Nevertheless for every . Thus the statement needs the additional hypothesis . If the course convention excludes the zero space, this hypothesis is already implicit.
Under this necessary hypothesis, density of implies that contains a nonzero vector. Given , scale that vector to obtain with , and choose . The triangle inequality gives
The centered closed ball is a symmetric Borel set. Apply the symmetric Gaussian translation lower bound to get
Hence the Gaussian norm distribution is strictly increasing when is nonzero. This proves the strict increase of a Gaussian norm distribution without assuming that its distribution has a density or that spheres have zero probability.
Suppose is a nonzero separable Banach space, the Cameron-Martin space of a Gaussian random variable in a Banach space is a dense subset of , and every centered ball of positive radius has positive probability. Then is strictly increasing on . For , choose in that Cameron-Martin space of a Gaussian random variable in a Banach space with and . The closed ball of radius centered at lies in the annulus and has positive probability by the symmetric Gaussian translation lower bound. The nonzero assumption is necessary: on the distribution function equals one everywhere.