The Theorem of the Cube says that the third finite difference of a line bundle on an abelian variety is trivial. On , it is the alternating tensor product of the pullbacks along the seven nonempty partial-sum maps.
For a line bundle on an elliptic curve over a number field, the geometric cube identity remains exact as a line-bundle identity. The Weil height machine translates it into the displayed bounded-error identity for a chosen logarithmic height, uniformly on the rational triples. This distinction is essential: arbitrary naive heights do not obey an exact quadratic identity. Dividing the identity for by produces an exact identity for the canonical height of an elliptic curve.
If a line bundle on is trivial on each zero-coordinate face, its First Chern class vanishes: the integral second cohomology consists of single-factor second cohomology and cross-products of first cohomology from pairs, and each summand is detected on a coordinate face. The holomorphic exponential sequence then puts the bundle in . The decomposition of first cohomology, including Dolbeault cohomology, identifies this group with . Triviality on the three coordinate axes makes all three factors trivial. Applying this cube principle to the alternating partial-sum pullbacks proves the usual addition-map Theorem of the Cube.
For group homomorphisms , this Picard group class is symmetric and additive in both arguments. The Theorem of the Cube says precisely that the third additive difference of vanishes, proving additivity of the cross-effect. The Poincaré line bundle expresses it as , so it depends only on the Néron-Severi group class of . Its associated homomorphism is .
For a line bundle on an abelian variety , this closed subgroup consists of such that . It is a stabilizer of a Picard group class, which need not be the same as the stabilizer of an individual Weil divisor representing that class.
The seesaw theorem determines a line bundle on a product from its restrictions to fibers: if it is trivial on all fibers over one factor and on one transverse section, then it is trivial.