Time reversal of an open migration process (${\nu }_i^{\ast }={\alpha }_i{p}_{i0},p_{ij}^{\ast }={\alpha }_j{p}_{ji}/{\alpha }_i,p_{i0}^{\ast }={\nu }_i/{\alpha }_i$)

For a stationary open migration process with local total departure rate ${\varphi }_i(n_i)$ and traffic rates ${\alpha }_i$, adjacent product-weight ratios give the displayed reversed parameters. The traffic equations of an open migration process make each reversed routing row sum to one, while total external arrival rates agree in the two directions. Thus the reversed process has the same local departure functions and is again an open migration process.

If no directed routing path returns from $k$ to $j$, the set of colonies reachable from $k$ has no outgoing edge to its complement. The complement is an autonomous open migration process, and the marked $j\to k$ transition is an exit from it. In time reversal of an open migration process, that exit is a state-independent Poisson immigration channel of rate ${\alpha }_j{p}_{jk}$. Reversing a stationary two-sided Poisson process preserves its law, proving the forward stream is Poisson. This argument does not assert Poisson internal streams for networks with feedback.