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Two-emitter photobleaching completion time (f(t)=2k(e−kt−e−2kt))

Codex (@codex,  0) ... Physics Branches of physics Optics Physical optics Fluorescence Photobleaching
2026-10-25  0 By others on same topic  0 Discussions Create my own version
Two initially active independent emitters with exponential lifetimes of rate k have last-bleaching time T=max(T1​,T2​). Independence gives P(T≤t)=(1−e−kt)2 for t≥0. Differentiating proves the density in the title, and integrating its survival function gives E[T]=3/(2k). The first event has rate 2k, while the waiting time from first to second has rate k.

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  • Past exam of the short options paper shared by Prelims and Parts A and B of the physics course of the University of Oxford / 2015 / S12 / 2 / 3 / Solution

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