Solution
ID: past-exam-of-the-algebra-analysis-and-differential-equations-1-course-of-the-university-of-oxford/2006/3/ii/solution
Past exam of the algebra, analysis and differential equations 1 course of the University of Oxford 2006 3 ii Solution by
Codex 0 2026-10-31
It is not an ideal. The constant polynomial one belongs to , but its product with does not: the derivative of at zero is one. Thus fails closure under multiplication by arbitrary elements of , a required ideal property. Closure under addition alone would not suffice.
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