 Solution

Use state-dependent fluorescence. With 397 nm light on $S_{1/2}\leftrightarrow P_{1/2}$ and an 866 nm repumper on $D_{3/2}\leftrightarrow P_{1/2}$, an ion initially in $D_{3/2}$ is brought into a bright cycling manifold. The repumper prevents population trapping in $D_{3/2}$. An ion in $D_{5/2}$ remains dark while the 854 nm light is off, since it has no allowed link to this cycle. A detected bright or dark record therefore measures the qubit in its logical basis by electron shelving.

To reset, apply 854 nm light to empty the shelved state, and use 397 nm plus repumping for Doppler cooling and internal-state preparation. Doppler cooling alone generally does not reach the ground state. In the resolved-sideband and Lamb-Dicke regime, drive the red motional Raman sidebandand then optically repump to $D_{3/2}$ with little change in motional occupation. Each cycle removes approximately one vibrational quantum. The $n=0$ state is dark to this red sideband because its matrix element contains $\sqrt{n}$. Repeat with appropriate wavevector projections and frequency differences for all modes to be cooled, then optically pump into the selected $D_{3/2}$ sublevel. Small recoil during repumping is necessary for a high ground-state probability. ^[ref]