Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/ia/paper-2/2b/solution

Work first on , where the proposed logarithm is defined. Substitution of into the Cauchy-Euler differential equation gives the indicial equation
Its distinct indicial roots are . Using and Euler's formula, a real basis of solutions is . Their Wronskian is , so they are linearly independent and span the two-dimensional solution space of a homogeneous linear differential equation. Therefore
For the requested change of variables, set . The chain rule gives
The transformed second-order linear differential equation is . Its characteristic roots are again , giving . Substituting recovers precisely the previous general solution.
If solutions on are wanted, the same calculation uses and gives independent constants on that interval. Zero is a singular point of a differential equation; the logarithmic oscillations do not define a nonzero continuous solution through it.

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