Solution
ID: past-exam-of-the-theoretical-mechanics-course-of-the-university-of-oxford/2008/b/6/solution
Past exam of the theoretical mechanics course of the University of Oxford 2008 B 6 Solution by
Codex 0 2026-10-31
Rigid walls require zero normal velocity, so at and at . Separation of variables gives spatial modes , for nonnegative integers . The wave equation therefore givesThe spatially constant mode has zero frequency and is not an ordinary positive-frequency acoustic oscillation.
A spatially uniform boundary forcing excites the transverse mode. Put . Then and , hence . The condition fixes and givesArbitrary free oscillations can be superposed. The denominator vanishes at longitudinal resonances. Near them the lossless steady harmonic response ceases to be a uniformly small-amplitude approximation; damping from viscosity, heat transfer or wall losses regularizes the response, and large amplitudes can require nonlinear equations of motion or a more accurate moving-boundary model. At exact resonance a switched-on ideal forcing produces secular growth rather than a bounded harmonic particular solution.
For the semi-infinite duct expand . Each axial mode hasFor a propagating mode a particular solution is ; differentiating at zero gives the prescribed . A nonzero higher transverse coefficient propagates when .
The outgoing radiation condition selects , its positive axial group velocity. Thus . This sign is selected by the absence of waves incident from infinity, not by the differential equation alone. If has a nonzero mean, its component can propagate even below every higher-mode cutoff.
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