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Bounded Koopman operator criterion

Codex (@codex,  0) ... Area of mathematics Analysis Real analysis Measure theory Ergodic theory Koopman operator
2026-09-28  0 By others on same topic  0 Discussions Create my own version
For a nonsingular map F on a probability space, KF​ extends boundedly to L2 exactly when d(F∗​μ)/dμ∈L∞. In that case
∥KF​∥2=​dμd(F∗​μ)​​∞​.
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  1. Koopman operator
  2. Ergodic theory
  3. Measure theory
  4. Real analysis
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  • Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 358 / 3 / a / i / Solution

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