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For an amine-first pathway, use triethylamine as a nucleophile in a reversible conjugate addition. Its lone pair attacks C3 of the enone; electron shifts through C2 and the carbonyl give a zwitterionic enolate with a C3–$\mathrm{NE}{\mathrm{t}}_3^{+}$ bond.

The C2 nucleophilic site of that enolate attacks $\mathrm{B}{\mathrm{r}}_2$, installing C2–Br and releasing bromide. Removal of C2–H by base then reforms C2=C3 while the C3–N bond breaks back to neutral triethylamine. This addition–bromination–elimination sequence gives the same C2-brominated enone and regenerates the nucleophilic amine, with another base equivalent accepting the eliminated proton.

These are alternative formal sequences requested by the question, not a kinetic determination that one must dominate under unspecified conditions. In particular, the amine-first sequence does not require triethylamine to generate a high concentration of a vinylic carbanion by direct deprotonation.

The first step is a vinylogous aldol condensation at C5 of the unsaturated lactam. Number nitrogen N1, the lactam carbonyl C2, and then the methoxy-substituted alkene C3=C4 and the methylene group C5.

hydroxide reversibly removes a C5 proton. The resulting vinylogous enolate is delocalized through C5–C4–C3–C2–O: it is not necessary to create an unstabilized isolated carbanion beside nitrogen. Its C5 nucleophilic contributor attacks acetone. protonation gives a C5-linked tertiary alcohol, $C5-\mathrm{C}(\mathrm{OH})(\mathrm{Me}{)}_2$. Further removal of the remaining C5 hydrogen and elimination through an aldol-dehydration sequence forms C5=C(Me)2, leaving the original methoxy enol ether in place.

In the second step, aqueous acid hydrolyses that enol ether to a ketone at C4. protonation at C3 gives an oxygen-stabilized cation at C4. water attacks C4, proton transfers form a hemiacetal-like intermediate, and loss of methanol followed by deprotonation produces C4=O and the C3 methylene group.

The lactam carbonyl and N–H group remain, as does the exocyclic isopropylidene group. This accounts for replacement of the C3=C4–OMe unit by C3H2–C4=O without inserting a new oxygen into the ring skeleton.

The acid initially protonates 1 and switches the system into the lithium-bound reporter state, so 512 nm intensity rises rapidly. The resulting carboxylate then decarboxylates irreversibly. Its carbanion removes the proton from 1, giving neutral waste 5 and restoring the original zinc/lithium distribution. Thus the 512 nm signal is a transient pulse followed by recovery to its initial low baseline; no repeated oscillations follow from one fuel addition.

For first-order decarboxylation the surviving fuel-derived carboxylate fraction is $e^{-kt}$ with $k=\ln 2/(75\min )$. If proton exchange and metal redistribution are fast, background is subtracted, and the population of the switched state is proportional to remaining protonated 1, the illustrative recovery isHalf the initial excess signal remains after 75 min and one quarter after 150 min in that limiting model. Actual binding equilibria can make the intensity nonlinear in remaining fuel; the supplied half-life fixes the fuel decay, not an exact reporter-intensity law. Monitor ${}^1$H NMR fuel consumption and waste formation alongside the optical trace to distinguish dissipation-driven recovery from photobleaching or simple dilution.