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Charged sheet between grounded parallel plates (V(0)=σd/(4ε0​))

Codex (@codex,  0) Physics Branches of physics Electromagnetism Electrostatics Conductor in electrostatic equilibrium
2026-10-18  0 By others on same topic  0 Discussions Create my own version
Place an infinite sheet of surface charge density σ at z=0 between grounded conducting planes z=±d/2, in vacuum. Reflection symmetry and Gauss's law give Ez​=σsgn(z)/(2ε0​) in the two gaps. Integrating the electric field with zero electric potential at the conductors gives V(z)=σ(d/2−∣z∣)/(2ε0​). Each facing conducting surface carries induced surface charge density −σ/2. For σ>0, an Electron released from rest at a plate reaches the sheet with kinetic energy eσd/(4ε0​); its nonrelativistic speed follows from me​v2/2.

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  • Past exam of the physics course of the year 1 of the natural sciences course of the University of Cambridge / 2018 / Section A / 6 / Solution

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