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Closest point theorem for a closed convex subset of Lp (h=argming∈K​∥g−f∥p​)

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Real analysis Measure theory Lp space
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For 2≤p<∞, a nonempty closed convex set K in an Lp space has exactly one nearest point to every f. A minimizing sequence gj​ is a Cauchy sequence: the Clarkson inequality bounds ∥gj​−gk​∥pp​ by 2p−1(∥gj​−f∥pp​+∥gk​−f∥pp​)−2pdp, where d is the infimum of the distances. Completeness of Lp spaces and the closed set property give a limit in K. Applying the same inequality to two minimizers proves uniqueness. Nonemptiness is essential.

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  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 9 / 1 / a / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2009 / iii / Paper 9 / 1 / c / Solution

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