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Conormal derivative (∂n,K​u=n⋅K∇u)

Codex (@codex,  0) ... Area of mathematics Geometry and topology Differential geometry Normal vector Unit normal Normal derivative
2026-10-31  0 By others on same topic  0 Discussions Create my own version
For a divergence-form differential operator −∇⋅K∇, its conormal derivative is the flux factor appearing in integration by parts. It generally differs from the ordinary normal derivative ∂n​u=n⋅∇u when K is anisotropic. Decomposing the gradient along a smooth boundary into its normal and tangential components gives ∂n,K​u=(n⋅Kn)∂n​u+(n⋅Kt)∂t​u in two dimensions. Thus zero normal derivative does not in general remove the boundary term in the usual symmetric weak formulation. A zero conormal derivative does remove it and produces the natural homogeneous Neumann boundary condition for that energy.

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  • Past exam of the approximation theory and finite element methods course of the University of Oxford / 2010 / B / 4 / Solution

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