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Work with real positive pulse envelopes and define $\Omega =\sqrt{{\Omega }_{12}^2+{\Omega }_{23}^2}>0$. Then $\cos \theta ={\Omega }_{12}/\Omega$ and $\sin \theta ={\Omega }_{23}/\Omega$. In the ordered basis $|1⟩,|2⟩,|3⟩$, the candidate dark state of a driven Hamiltonian has coordinatesMultiplication by the given rotating-wave approximation matrix givesThusIts absence of an excited-state component is the destructive interference that makes it dark. The orthogonal bright ground-state combination is $|B⟩=\cos \theta |1⟩+\sin \theta |3⟩$. Since $H|B⟩=\Omega |2⟩$ and $H|2⟩=\Omega |B⟩$, the two remaining eigenstates are $(|B⟩\pm |2⟩)/\sqrt{2}$ with eigenvalues $\pm \Omega$.

For signed envelopes, use a continuous two-argument angle with $\cos \theta ={\Omega }_{12}/\Omega$ and $\sin \theta ={\Omega }_{23}/\Omega$, rather than an ambiguous arctangent branch. When both fields vanish, every state has zero eigenvalue and this formula does not select a unique dark vector.

For $|D⟩=(|1⟩-|3⟩)/\sqrt{2}$, direct multiplication gives $H_1|D⟩=0$ and $H_0|D⟩=-\omega |D⟩$. It is therefore a dark state of a driven Hamiltonian for every real control, andStarting from this state, the reachable physical ray is a singleton, so it cannot be transferred to $|2⟩$ or any distinct ray. More generally $P_D=|D⟩⟨D|$ commutes with both generators; hence $\mathrm{Tr}(P_D\rho )$ is conserved. The system thus fails full-qutrit pure-state controllability, density operator controllability, and unitary operator controllability.

This is the appropriate full-space meaning of the PDF's phrase about all senses of controllability. It does not preclude control within a restricted invariant subspace: the bright state $|B⟩=(|1⟩+|3⟩)/\sqrt{2}$ couples to $|2⟩$ with strength $\sqrt{2}df(t)$, while the dark line is isolated. The bright and dark state reduction of a star-coupled Hamiltonian makes that invariant decomposition explicit.

The adiabatic dark state of a driven Hamiltonian has exactly zero component on the lossy intermediate level throughout the ideal passage. It therefore suppresses spontaneous emission, whereas the two-pulse route explicitly transfers the population into $|2⟩$ before moving it to $|3⟩$. For an intermediate-level decay rate $\Gamma$, the leading loss probability is controlled by $\Gamma \int P_2(t)dt$. In stimulated Raman adiabatic passage, nonadiabatic leakage makes $P_2$ of order $(\hslash \dot{\theta }/\Omega {)}^2$, rather than the order-one intermediate population of the sequential swaps. Transfer is also less sensitive to precise pulse areas, provided the ordering, gap and slowness requirements hold. Making the process slower indefinitely is not always beneficial if the outer states also decohere; their coherence must survive the total passage duration.

For a resonant three-level chain with couplings ${\Omega }_1,{\Omega }_2$, the zero-energy dark state of a driven Hamiltonian is $|D⟩=({\Omega }_2|1⟩-{\Omega }_1|3⟩)/\sqrt{{\Omega }_1^2+{\Omega }_2^2}$. Turning on the target-to-intermediate coupling first and sweeping ${\Omega }_1/{\Omega }_2$ from zero to infinity rotates this state from $|1⟩$ to $-|3⟩$. The other eigenvalues are $\pm \sqrt{{\Omega }_1^2+{\Omega }_2^2}$, so $\hslash |\dot{\theta }|\ll \sqrt{{\Omega }_1^2+{\Omega }_2^2}$ controls nonadiabatic leakage. Ideally the intermediate state remains unoccupied, suppressing spontaneous-emission loss. The gap must not close while the dark state is rotating.