Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 1 17I c Solution Created 2026-09-24 Updated 2026-10-03
First consider a -free bipartite graph with parts , each of size at most , and edges. Count pairs in which is a -element subset of the graph neighbourhood of . Any vertices of have at most common neighbours, since common neighbours would form the complete bipartite graph . ConsequentlyIf the average degree of a vertex is bounded in terms of , then and the required result is immediate. Otherwise, convexity of and the preceding inequality giveand hence . Every graph has a bipartite spanning subgraph containing at least half its edges, obtained by choosing a random bipartition. Applying the bipartite estimate to that subgraph proves the Kővári–Sós–Turán theorem in the required form:
The stated "nice" subsets of the finite cyclic group are Sidon sets. Ifthen . Niceness forces ; the alternative pairing would force . Thus the ordered nonzero differences are distinct elements of the nonzero residue classes. Thereforeso
In the standard labelled encoding of a pointed planar quadrangulation, incidences at the distinguished vertex are represented by visits counted by the record variables . Consequently its degree of a vertex is bounded by the largest such count encountered before the coding walk first reaches .
Trifurcation boundary-counting lemma 2026-10-06
For a finite graph vertex set in a locally finite graph, let be its exterior graph neighbours. The number of trifurcation vertices in percolation lying in is at most .
For each cluster meeting , contract its connected components of a graph outside to terminal graph vertices, keeping only those adjacent to . The resulting incidence graph is finite and connected. Each trifurcation graph vertex in separates at least three groups of terminals, because every infinite branch must leave the finite set . Take a minimal subtree connecting all terminals. Each such trifurcation is unavoidable in that subtree and has degree of a vertex at least three. All leaves are terminals. The tree identity bounds the number of these branching graph vertices by the number of leaves minus two, hence by the number of terminals. Different terminals, even across different clusters, can be assigned different exterior graph neighbours. Summing proves the bound. For square boxes in , the boundary has order and the volume has order .