Eleven-dimensional supergravity ($G_{MN},A_{MNP},{\Psi }_M$)

Eleven-dimensional supergravity contains a metric, a three-form potential and a gravitino. Its bosonic on-shell counts are $11(11-3)/2=44$ for the metric and $\left(\genfrac{}{}{0ex}{}{9}{3}\right)=84$ for the three-form, totaling $128$. Flat toroidal zero-mode reduction gives type IIA supergravity in ten dimensions and four-dimensional N=8 supergravity in four dimensions without losing these bosonic polarizations.

// Target: supersymmetry.bigb

A product compactification supported by a four-form proportional to one factor's volume form. For the maximally supersymmetric membrane throat, the other factor is a round $S^7$ and the radii obey $R_{S^7}=2R_{\mathrm{AdS}}$. The flux links the curvature scales through the supergravity field equations.

With the membrane Freund-Rubin compactification flux and the required radius ratio, the Killing spinor equation separates into AdS4 and sphere equations with correlated signs. The respective real solution dimensions are four and eight, giving thirty-two. The associated Killing-spinor connections have vanishing curvature for these choices, so arbitrary initial spinor data generate solutions locally; standard global spin structures give the usual maximally supersymmetric background.

// Target: geometry-and-topology.bigb

Circle reduction splits the metric into a ten-dimensional graviton, one vector and one scalar, and the three-form into a three-form and two-form. Seven-torus reduction gives a four-dimensional graviton, $7+21=28$ vectors, $28+35$ direct scalars and seven two-forms. The two-form scalar duality turns the latter into seven more scalars, giving $70$ in all. A remaining four-dimensional three-form has no local polarization. These are zero-mode counts without fluxes, orbifold projections or moduli freezing.

For circle-independent fields, the metric gives the type-IIA string-frame metric, dilaton and RR one-form. Decomposing $A_3=C_3+B_2\wedge dy$ gives the RR three-form and Kalb–Ramond field. With $H_3=d{B}_2$, $F_2=d{C}_1$, the horizontal four-form is ${\tilde{F}}_4=d{C}_3-C_1\wedge H_3$. The Einstein term reduces, modulo a total derivative, to $\sqrt{-g}[e^{-2\Phi }(R+4(\nabla \Phi {)}^2)-\frac{1}{4}{F}_{2,\mu \nu }{F}_2^{\mu \nu }]$. The eleven-dimensional form norm gives $\sqrt{-g}[e^{-2\Phi }|H_3{|}^2+|{\tilde{F}}_4{|}^2]$, where $|F_k{|}^2=F^2/k!$. Ordinary reduction generates massless type IIA supergravity, not Romans mass.

Put $A_3=C_3+B_2\wedge dy$ and $F_4=G_4+H_3\wedge dy$, where $G_4=d{C}_3$. The circle component of $A_3\wedge F_4\wedge F_4$ is $[B_2\wedge G_4\wedge G_4+2C_3\wedge G_4\wedge H_3]\wedge dy$. Since $d(C_3\wedge B_2\wedge G_4)=B_2\wedge G_4\wedge G_4-C_3\wedge H_3\wedge G_4$, its integral equals three copies of $B_2\wedge G_4\wedge G_4$ up to a boundary term. The coefficient therefore becomes $-1/2$ after circle integration. Boundary terms and global potential patching must be retained when the spacetime has boundary or nontrivial flux topology.