Let be mutually independent, with identically distributed. Entropy submodularity for three independent sums gives
Independent addition cannot decrease discrete entropy, because . Hence
Take to have the distribution of and take to be independent copies of , all mutually independent. Then and both have the distribution of , whereas has the distribution of and . Hence
or
The denominator is nonnegative because conditioning on recovers from , so .
Because are independent random variables, adding is an independent noise channel, so
is a Markov chain. The data processing inequality for mutual information gives
Translation in the finite additive group preserves conditional entropy, and independence therefore gives
and
Substitution proves the required entropy submodularity for three independent sums.
Write , , , and . Distances depend only on distributions, so all variables used in any one application may be realized as independent random variables.
First, the entropy submodularity for three independent sums implies
and analogously for . The Entropic Ruzsa triangle inequality gives and . Consequently the relevance of independent self-sums gives
Apply the Conditioned entropic Ruzsa distance of a summand first to and then to :
Three applications of the Entropic Ruzsa triangle inequality give
Adding all these bounds yields
Thus the required absolute constants may be taken as and .
Independence makes
a Markov chain. The data processing inequality for mutual information therefore gives . Translation by the known value of is a bijection, so conditional entropy and independence give
and . Rearranging proves the stated entropy submodularity for three independent sums:
Relevance of independent self-sums Created 2026-09-24 Updated 2026-09-24
If is -relevant to and are mutually independent copies, then is -relevant to . The entropy submodularity for three independent sums implies
and similarly for . The Entropic Ruzsa triangle inequality bounds
which proves the claim after addition.