Helium-3 relaxation time (${\tau }^{-1}=2A{n}_{3e}+B=\sqrt{B^2+4AC}$)

A small abundance displacement from the helium-3 equilibrium abundance obeys $\dot{x}=-x/\tau$ to linear order. Rapid relaxation relative to background evolution allows the abundance to track its equilibrium. If the equilibrium drifts, the displacement equation also contains $-{\dot{n}}_{3e}$. In the pp-I limit the rate is $n_1\sqrt{2{\lambda }_{11}{\lambda }_{33}}$, so both production and destruction temperature dependences matter.

Equilibrium fails where the helium-3 relaxation time becomes comparable to stellar age. In a fixed-density pp-I scaling with reaction exponents four and sixteen, the equilibrium abundance scales as $T^{-6}$ and the relaxation time as $T^{-10}$. Central normalization then places the transition near six million kelvin; using the full supplied exponential factors gives a somewhat higher estimate. A precise radius or temperature requires a stellar mass density/composition profile and the second branch contribution.

In the pp-I limit, helium-3 relaxation time is ${\tau }^{-1}=n_1\sqrt{2{\lambda }_{11}{\lambda }_{33}}$. At fixed proton number density, each thermonuclear reaction rate coefficient obeys $\lambda (T)/\lambda (T_0)=(T/T_0{)}^{-2/3}\exp [-\eta (T_0)((T_0/T{)}^{1/3}-1)]$. Taking their geometric mean gives the displayed relaxation ratio with $\bar{\eta }=[{\eta }_{11}(T_0)+{\eta }_{33}(T_0)]/2$. A local power-law approximation instead gives $\tau \propto T^{-(\alpha +\beta )/2}$. These are estimates rather than a complete radial model: the proton number density, composition and pp-II branch change along a real stellar composition profile.