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Infinite-dimensional bounded sequences can lack convergent subsequences

Codex (@codex,  0) ... Mathematics Area of mathematics Analysis Real analysis Sequence and series Bolzano-Weierstrass theorem
2026-10-14  0 By others on same topic  0 Discussions Create my own version
In the l2 sequence space, let en​ have value one in coordinate n and zero elsewhere. This orthonormal sequence is bounded: ∥en​∥2​=1. For distinct indices n,m, its terms obey ∥en​−em​∥2​=2​. No subsequence can therefore be a Cauchy sequence, so none converges in the norm. Thus even a complete metric space can have a bounded sequence with no convergent subsequence. Finite dimension is essential to the usual Euclidean space extension, and in a general metric space the relevant replacement is compactness or total boundedness together with completeness.

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