Since the initial velocity vanishes, D'Alembert's formula reduces to
Each translated copy has half the original amplitude. To identify each requested cross-section, track the translated support intervals and add the values where they overlap.
At , is supported on and on . On these intervals , so
The pieces meet continuously at zero, where both contributions vanish.
At , the support of is ; that of is . In the central overlap,
so the two contributions cancel. The remaining wave profile is
For the time cross-section at the origin, the initial profile is an odd function, so
For the time cross-section at , the left-travelling contribution is nonzero for and equals . The right-travelling contribution is nonzero for and also equals . At the common endpoint both vanish. Hence
The following graphs show all four cross-sections. In particular, the last trace reaches at and at .
Figure 1.
The four requested cross-sections of the wave equation solution
. The upper panels show the spatial profiles at and . The lower panels show the time traces at and for . Horizontal axes are labelled in multiples of . Details.
Because , restriction to the half-line solves the following initial-boundary value problem with a homogeneous Dirichlet boundary condition:
This is wave reflection by odd extension. If a condition at infinity is desired, take the solution with finite wave energy; here the profile has bounded support at every finite time.
The initial profile is continuous and piecewise continuously differentiable, but its first derivative jumps at the support endpoints. Thus the formula gives a weak solution globally and a piecewise classical solution away from the characteristic lines for the one-dimensional wave equation issuing from those endpoints. The initial velocity is zero in the square-integrable function sense and pointwise wherever the initial profile is differentiable; at the kink points a pointwise right time derivative need not equal zero. This regularity qualification is needed for the given data.
For the half-line wave equation with a zero Dirichlet boundary condition at , extend both the initial displacement and initial velocity as odd functions to the full line. D'Alembert's formula then gives an odd solution in , so . Restriction to solves the desired initial-boundary value problem. With zero initial velocity, the displayed formula shows reflection at the fixed endpoint with reversal of the displacement sign. Continuous piecewise smooth displacement data give a weak solution; a classical solution requires sufficient additional regularity. In particular, a kink in the initial displacement can prevent the pointwise time derivative at that kink from taking the assigned initial velocity, even though the initial velocity is attained in the sense.