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An angular isotropy test with planar irradiance measurements rotates a characterized receiver to test whether its readings agree with a specified model of an isotropic radiance field. A one-sided ideal cosine receiver measures $E(\mathbf{n})=\int L(\mathbf{\omega })\max (0,\mathbf{n}\cdot \mathbf{\omega })d\Omega$. Constant radiance gives the same $\pi L_0$ for every normal. Instrument angular response needs characterization; the primary guide describes experimental correction of cosine receptors.^[ref]

An original restricted-model example makes the inference quantitative. Assume a dipole anisotropy of a radiance field,Hemisphere integration gives $E(\mathbf{n})=\pi L_0[1+(2ϵ/3)\mathbf{a}\cdot \mathbf{n}]$. For $L_0=1\mathrm{W}{\mathrm{m}}^{-2}\mathrm{s}{\mathrm{r}}^{-1}$, $ϵ=0.30$ and $\mathbf{a}$ along the vertical axis, upward/downward-facing receivers give $1.2\pi$ and $0.8\pi \mathrm{W}{\mathrm{m}}^{-2}$. Their difference divided by their sum is $0.20$, implying $ϵ=0.30$ within this chosen model.

Use the same receiver position, background treatment and a stable source monitor while changing orientation. Gain drift or moving into a different spatial field can otherwise imitate an angular effect. A finite set of readings tests the assumed angular family; it does not prove unrestricted isotropy. The six-beam counterexample in isotropic radiance field shows why a few equal axis readings can miss other directional structure.

The first angular moment of a radiance field is the vectorwith units $\mathrm{W}{\mathrm{m}}^{-2}$ for frequency-integrated radiance. It records a directional imbalance. Here $\mathbf{\omega }$ is the viewing direction toward the arriving light, as in dipole anisotropy of a radiance field; using propagation directions instead reverses the vector. With that convention change, this is the bolometric vector form of the radiative flux, an existing radiation-field moment.

Opposite ideal planar receivers measure this moment without assuming a pure dipole. Since $\max (0,x)-\max (0,-x)=x$, the cosine-response irradiance formula givesThree orthogonal receiver pairs therefore determine the three components. For original differences $(0.60,-0.20,0.30)\mathrm{W}{\mathrm{m}}^{-2}$, the moment has those components and magnitude $0.70\mathrm{W}{\mathrm{m}}^{-2}$. The derivation requires the same spatial field, stable gains and known angular response. The primary optical guide describes cosine-receptor characterization rather than assuming it perfect.^[ref]

A zero first moment does not establish an isotropic radiance field. For example, two equal oppositely directed collimated beams have cancelling vector moments while remaining strongly directional. Conversely, any nonzero first moment rules out isotropy. The scalar all-direction integral $J=\int Ld\Omega$ bounds the moment by $|\mathbf{M}|\le J$ for nonnegative radiance, by the triangle inequality and $|\mathbf{\omega }|=1$.

Within the restricted dipole anisotropy of a radiance field model, $\mathbf{M}=(4\pi /3)L_0\mathbf{b}$ determines its dipole vector. More general angular structure is not reconstructed by these three numbers. Opposed receivers reveal the first moment, not the entire directional distribution.

Spherical irradiance counts incident radiance from all directions without selecting a receiving-plane normal. Using the projected-area convention specified in the CIE entry's note2,Here $d\Omega$ is an element of solid angle. An ideal small sphere of radius $a$ intercepts radiant flux ${\Phi }_{\mathrm{in}}=\pi a^2{E}_{\mathrm{e},\mathrm{o}}$. The denominator is its diametrical projected area, not its full surface area.^[ref]

For an original isotropic radiance field example, take $L_{\mathrm{e}}=L_0=2\mathrm{W}{\mathrm{m}}^{-2}\mathrm{s}{\mathrm{r}}^{-1}$ in every direction. Then $E_{\mathrm{e},\mathrm{o}}=4\pi L_0=8\pi \mathrm{W}{\mathrm{m}}^{-2}$. A one-sided plane instead receivesThe factor four follows from the different angular geometries; it is not a unit conversion. Averaging the sphere's intercepted power over its actual $4\pi a^2$ surface also gives $E_{\mathrm{e},\mathrm{o}}/4$, rather than the projected-area-normalized quantity above.

An all-direction receiver must have a characterized angular response. A single flat irradiance detector inherently samples a hemisphere with projected-area weighting, so rotating it or enclosing it in a diffuser does not supply an all-direction value without an appropriate response model and measurement calibration. Report the angular and area conventions with the result; equal units do not make irradiance and spherical irradiance interchangeable.