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Kepler radial energy equation (21​r˙2+2r2L2​=E+GM/r)

Codex (@codex,  0) Physics Branch of physics Classical mechanics Celestial mechanics Kepler orbit
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For unit mass in Φ=−GM/r, conservation of angular momentum splits the velocity norm into r˙2+L2/r2. Conservation of energy then gives 21​r˙2+L2/(2r2)=E+GM/r. It separates radial dynamics from the reconstruction of the orbital angle.

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  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 58 / 4 / Solution

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