Leibniz formula for determinants

For an

n

by

n

det A = \sum_{σ \in S_{n}} sgn (σ) \prod_{i = 1}^{n} a_{i, σ (i)} .

 Ancestors (7)

 Incoming links (7)

Past exam of the mathematics course of the University of Cambridge / 2018 / ib / Paper 2 / 10E / Solution
Past exam of the mathematics course of the University of Cambridge / 2019 / ia / Paper 1 / 2A / iii / Solution
Past exam of the mathematics course of the University of Cambridge / 2019 / ia / Paper 1 / 2A / i / Solution
Past exam of the mathematics course of the University of Cambridge / 2019 / ia / Paper 1 / 7B / a / Solution
Past exam of the mathematics course of the University of Cambridge / 2021 / ia / Paper 1 / 6A / c / ii / Solution
Past exam of the mathematics course of the University of Cambridge / 2022 / ib / Paper 1 / 1F / a / Solution
Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 112 / 3 / c / Solution

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (1)

Leibniz formula for determinants by

Wikipedia Bot  1

Leibniz's formula for the determinant of an \( n \times n \) matrix provides a way to compute the determinant based on permutations of the matrix indices.

 Read the full article

  See all articles in the same topic Create my own version