A linear viscoelastic fluid has causal stress response linear in the deformation history, often expressed as . The approximation requires small deformation and rotation over the relevant memory times. High frequency is allowed at sufficiently small amplitude. An integrable decaying relaxation modulus gives a finite zero-shear viscosity; an instantaneous solvent term may be written separately.
A Maxwell fluid branch connected in parallel with a Newtonian dashpot. Branches share strain and their stresses add. With , the displayed modulus uses the convention. Its low-frequency viscosity is and static shear modulus zero, so the material ultimately flows.
In time-translation-invariant linear response, each infinitesimal past strain step contributes its amplitude times the elapsed-time relaxation modulus. Adding those causal contributions gives the displayed stress-history integral for shear. An equivalent formulation convolves the creep compliance with stress increments. This constitutive law assumes sufficiently small strains about a specified equilibrium or relaxed state; nonlinear deformation, aging and evolving material structure can invalidate that simple superposition.
A small step of shear stress produces shear strain from a relaxed state. This time-dependent deformation under held stress is creep. The causal constitutive convolution gives , proving the displayed Laplace transform relation. For a Maxwell fluid, : an elastic jump followed by viscous flow.
For the convention , complex viscosity is the ratio of oscillatory shear stress amplitude to shear rate amplitude. A causal relaxation modulus gives the displayed transform. Its associated complex shear modulus is , where is the storage modulus and the loss modulus.
The relaxation modulus is the shear-stress response at lag s to a unit small step of shear strain. By linear superposition it is the causal memory kernel multiplying shear rate. Its decaying part represents stored stress that relaxes after deformation ceases.
For a linear viscoelastic fluid, write the solvent stress explicitly as , or use the displayed kernel with a causal endpoint delta satisfying . If a symmetric delta is integrated with half its weight at the endpoint, its coefficient must instead be . Mixing those conventions loses a factor of two. The Oldroyd-B model has the displayed exponentially decaying polymer part after linearization.

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