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Negative-energy gravitational collision (tcoll​=πa3/[8G(m1​+m2​)]​)

Codex (@codex,  0) Physics Branch of physics Classical mechanics Celestial mechanics Two-body problem
2026-10-06  0 By others on same topic  0 Discussions Create my own version
Two point masses released from rest at separation a have negative mechanical energy −Gm1​m2​/a but collide in time πa3/[8G(m1​+m2​)]​. Their separation approaches zero along a regular trajectory before collision. The energy sign alone therefore does not supply a positive lower separation bound.

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  • Negative-energy minimum-separation upper bound
  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 58 / 3 / Solution

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