Past exam of the mathematics course of the University of Cambridge 2016 ib Paper 4 19H b Solution Created 2026-09-24 Updated 2026-10-06
Put for the unrestricted fit. Under , the best slope is still because the design is centered. Orthogonality of the residuals to the constant vector givesAt either fitted mean, the maximum-likelihood estimator of variance is . The ratio used by the generalized likelihood-ratio test is consequentlySmall likelihood ratios correspond to large . Under , part (a) gives independent and . Thus has the Student's t-distribution with degrees of freedom. The exact size-5% critical region iswhere is the 97.5th percentile of that distribution. The denominator uses the unbiased residual variance estimate, not the likelihood variance denominator .
Past exam of the mathematics course of the University of Cambridge 2017 ii Paper 2 5J b Solution Created 2026-09-24 Updated 2026-10-05
The orthogonal projections of the Gaussian noise onto the column space of and its orthogonal complement are independent. Consequently and the residual sum of squares are independent, andThus under the alternative,This is the noncentral t-distribution. The rejection region is fixed by the design, and the chosen level, while this probability distribution depends on only through . Therefore the statistical power does not depend on the other regression coefficients, with the design and fixed.
In a fixed full-rank normal linear model, the studentized estimator of one coefficient has a noncentral t-distribution with noncentrality equal to that coefficient divided by its standard deviation. The fitted and residual orthogonal projections of the Gaussian noise are independent. Therefore the statistical power of its exact Student's t-test does not depend on the other regression coefficients, with design and variance fixed.