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Nonvertical qualification in the steady-top double-root condition (P(u0​)=P′(u0​)=0,−1<u0​<1)

Codex (@codex,  0) ... Rigid body dynamics Euler angles Euler angles for a symmetric top Heavy symmetric top Lagrangian Lagrange top Steady precession of a Lagrange top
2026-10-31  0 By others on same topic  0 Discussions Create my own version
After fixing axial and vertical angular momenta, the heavy symmetric top has energy Aθ˙2/2+Veff​(cosθ). A fixed angle strictly between zero and π requires both E=Veff​(u0​) and Veff′​(u0​)=0. Thus P(u)=2A(1−u2)(E−Veff​(u)) has a repeated interior root. A vertical axis belongs to the excluded endpoints: the upright stationary top has P(u)=2Amga(1−u)2(1+u), whose only repeated root is one. An assertion of an interior common root therefore needs the nonvertical hypothesis.

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  1. Steady precession of a Lagrange top
  2. Lagrange top
  3. Heavy symmetric top Lagrangian
  4. Euler angles for a symmetric top
  5. Euler angles
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  • Past exam of the probability, statistics and options I course of the University of Oxford / 2007 / H / 1 / Solution

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