Past exam of the chemistry A course of the University of Cambridge / 2021 / Paper 1 / A3 / a / ii

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- Solution ii

Solution

x

from the carbon nucleus toward the sulfur nucleus. The definition of the center of mass gives

x_{cm} = \frac{m _{C} 0 + m _{S} r}{m _{C} + m _{S}} .

Therefore the requested distance is

r_{1} = \frac{m _{S}}{m _{C} + m _{S}} r .

The other distance is

r_{2} = r - r_{1} = m_{C} r / (m_{C} + m_{S})

, consistent with

m_{C} r_{1} = m_{S} r_{2}

.

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