Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge / 2022 / Paper 2A / Section A / 15 / c / i / Solution

Here ${\Delta }_o/B=20$, so the ground term is ${}^6{A}_{1g}$. There are no spin-allowed d–d bands in the displayed manifold under the spin selection rule: the excited terms shown have doublet or quartet rather than sextet multiplicity. Very weak spin-forbidden absorptions can still gain intensity through spin–orbit coupling, and even spin-allowed d–d transitions would be forbidden by the Laporte rule in ideal centrosymmetric coordination. Thus a strong ordinary d–d spectrum should not be predicted simply by multiplying the splitting by a numerical factor. For scale, the lowest quartet branches read roughly $E/B\simeq 17,23,33$ at this abscissa, corresponding to weak features around $1.4\times 10^4$, $1.8\times 10^4$ and $2.6\times 10^4\mathrm{c}{\mathrm{m}}^{-1}$ if such forbidden intensity is detectable. These are graphical estimates, not precision assignments of every weak line.