Past exam of the chemistry course of the year 3 of the natural sciences course of the University of Cambridge / 2022 / Paper 4 / 64 / d / ii

$0.1\mathrm{M}=100\mathrm{mol}{\mathrm{m}}^{-3}=10^5\mathrm{mmol}{\mathrm{m}}^{-3}$. ThereforeThe surface is almost saturated, so the rate approaches the supplied limiting constant. This assumes rapid adsorption equilibrium, negligible product coverage, no competing species and unchanged substrate area/photochemical conditions.