Let be the affine hull and put . If , is a singleton and is homeomorphic to . Suppose . Choose affinely independent points of spanning . Their simplex is contained in because is a convex set, and its barycentre has a neighbourhood in contained in that simplex. Identifying with , put . For some ,
Here the inner inclusion follows from that neighbourhood, and the outer one follows from the compactness of .
Use the Minkowski functional
The inclusions imply . The fact that is a convex set implies : if and , then is a convex combination of points of . Also for . Consequently
Thus is a continuous function. Since is closed and contains zero, : the forward inclusion is immediate, and for the reverse inclusion one takes a limit of with , using positive homogeneity and the fact that is a convex set. For , , so this limiting argument has no division by zero.
Define a radial continuous map by
Each ray meets in exactly . Hence is a bijection from to . Away from zero its continuity follows from that of , and at zero . A continuous map that is a bijection from a compact space to a Hausdorff space is a homeomorphism. Therefore
Using the affine hull is essential: can have empty interior in the ambient .

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