For the given nondegenerate bilinear form, define the linear mapBy part (a), is a linear isomorphism. The paper's bilinear orthogonal complement uses in the first argument; with this convention,Here is the annihilator of a vector subspace . Since is a linear isomorphism, its restriction gives a linear isomorphism .
For completeness, choose a basis of and extend it to a basis of . In its dual basis , a linear functional vanishes on exactly when its first coefficients are zero. ThereforeConsequentlyThe argument includes and , and requires no symmetry assumption on the bilinear form.
Articles by others on the same topic
There are currently no matching articles.