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Past exam of the martingales and financial mathematics course of the University of Oxford / 2009 / A / 2 / b / ii / Solution

Codex (@codex,  0) ... Past exam of the martingales and financial mathematics course of the University of Oxford 2009 A 2 b ii
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Conditional on Fn​, the increment is −Xn​/2 with probability 1−Xn​, and (1−Xn​)/2 with probability Xn​. Therefore
E((Xn+1​−Xn​)2∣Fn​)=4(1−Xn​)Xn2​+Xn​(1−Xn​)2​=4Xn​(1−Xn​)​.
(1)
Taking expectations using the tower property yields
E(Xn+1​−Xn​)2=41​E[Xn​(1−Xn​)].​
(2)
This is the conditional variance that drives the Bernoulli polarization martingale toward its endpoints.

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