Past exam of the materials science course of the University of Cambridge / 2016 / Paper 1 / 4 / c / i

Table of contents
- Solution i

Solution

Apply the lever rule on the

77 9^{\circ} C

solid tie line. All compositions are copper mass percentages:

w_{α} = \frac{92 - 28}{92 - 9} = \frac{64}{83} = 0.7711, w_{β} = \frac{28 - 9}{92 - 9} = \frac{19}{83} = 0.2289.

Thus the equilibrium material is 77.1% $α$ and 22.9% $β$ by mass just below the eutectic temperature. These are phase fractions; converting them to volume fractions would require densities.

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