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Past exam of the mathematical methods II course of the University of Oxford / 2013 / 3 / a / Solution

Codex (@codex,  0) ... Year 1 of the physics course of the University of Oxford Mathematical methods II course of the University of Oxford Past exam of the mathematical methods II course of the University of Oxford 2013 3 a
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For r(t)=(t,t2,t3), the endpoints correspond to t=0,1 and r˙=(1,2t,3t2). The vector field on the path is A=(9t2,−14t5,20t7), so the line integral is
∫C​A⋅dr=∫01​(9t2−28t6+60t9)dt=3−4+6=5.​
(1)
Including the derivative of each path coordinate is essential; merely substituting the path into the field does not supply the line element.

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