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Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 7 / 1 / v / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 7 1 v
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
The hypothesis puts zero in the common unbounded resolvent component from part (iii). Hence 0∈ρB​(x) for B=C[1,x]​, and (−x)−1∈B, or equivalently x−1∈B. By the definition of this norm closure, for each n choose a polynomial pn​ with ∥pn​(x)−x−1∥<1/n. Therefore
pn​(x)⟶x−1.​
(1)
This is an approximation in the algebra norm, not merely a scalar approximation on the Banach algebra spectrum.

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