For constant particle masses define the centre of mass by , with . Summing Newton's second law over all particles givesEach pair of internal forces cancels by Newton's third law. HenceOnly the action-reaction condition is needed for this translation law; centrality of the internal forces is needed for the angular momentum result in part (ii).
About a fixed inertial origin, the total angular momentum is . Differentiation givesbecause . Separate the external and internal contributions. The combined torque of an internal pair isThe first equality uses Newton's third law, and the second uses the given central-force condition. All internal torques therefore cancel, leavingAn equal-and-opposite pair which is not central need not have zero combined torque; this explains why both internal-force hypotheses matter.
Write and , where . The definition of the centre of mass and its derivative giveExpand the total angular momentum:The two middle terms vanish. Thus the angular momentum decomposition about the centre of mass isThe first term is orbital angular momentum of the centre; the second is angular momentum about the centre of mass.
Let and . A differentiable central potential energy gives the internal forcesThere are no external forces. Differentiating the total kinetic energy and using Newton's second law therefore givesSince , the last expression is . ThusThis conserves total mechanical energy, including the kinetic energy of centre-of-mass motion, not merely the relative kinetic energy.
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