Use a common invariant operator domain on which the stated differentiations and commutator are valid. For a differentiable normalized eigenfunction, the Hellmann-Feynman calculation and self-adjointness give
The Lax equation preserves the spectrum. Differentiating now gives , so is in the same eigenspace, or is zero. For a nondegenerate eigenvalue it equals . Multiplying by produces with while preserving its eigenvalue.
Write and . The spatial eigenvalue equation gives , so . For the two first-order systems are therefore
The second row of follows by differentiating the first time equation in and using the spatial equation once more. Conversely these matrix equations imply both scalar equations, so the formulations are equivalent.

Articles by others on the same topic (0)

There are currently no matching articles.