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Past exam of the mathematics course of the University of Cambridge / 2014 / ia / Paper 3 / 10A / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2014 ia Paper 3 10A a
Created 2026-09-24 Updated 2026-10-06  0 By others on same topic  0 Discussions Create my own version
For an oriented piecewise smooth surface S and a continuously differentiable vector field on a neighborhood of it, Stokes theorem states
∫S​(∇×F)⋅dS=∮∂S​F⋅dx.​
(1)
The oriented surface element and boundary direction must agree by the right-hand rule. Every boundary component is included; for an upward-oriented graph over an annulus the outer boundary is anticlockwise and the inner boundary clockwise when viewed from above.

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