Take and a positive prescribed distance ; if , the zero-speed journey has zero cost. Minimize subject to and the isoperimetric constraint . Introduce a constant Lagrange multiplier and the integrand . For a variation with , integration by parts givesThe interior Euler-Lagrange equation isWhen terminal speed is free, the same calculation also imposes the natural boundary conditions for a free endpoint:One cannot drop this boundary term when interpreting an extremal as a genuine minimum. If , the interior condition makes constant; with a continuous zero initial speed and it cannot be attained. In that case Cauchy-Schwarz inequality gives the infimum , approached by speeds nearly constant except in a short initial layer. For , the derivative cost controls such layers and the natural terminal condition matters in parts (b) and (c).
Put . Solving the interior Euler-Lagrange equation and imposing both and yields , with . The distance constraint fixesThe denominator is positive because for . This is the requested solution of the differential equation with the stated initial conditions.
As a minimum-energy problem with free terminal speed, the printed conditions do not admit a smooth minimizer. The formal profile has , violating the natural terminal condition from part (a). Fixing the initial acceleration restricts , but it does not restrict the independently variable and therefore does not remove that condition.
For clarity, without the extra initial-acceleration restriction the actual unique minimizing profile isIt satisfies , , the distance constraint and the interior equation, but . For any perturbation preserving the distance and initial speed, the first variation about is zero, andwith equality only for . Its energy is .
This same energy is the unattained infimum under the extra condition . Indeed multiply by and rescale by a factor tending to one to restore total distance . These smooth nonnegative profiles have both initial values zero and converge to in value and derivative square integrals as . Their energies tend to , but uniqueness of precludes attaining it with zero initial acceleration. This is nonattainment under an initial derivative constraint.
Here because and the two cost coefficients are not both zero. The interior Euler-Lagrange equation makes quadratic. Imposing each displayed pair of endpoint data and the distance constraint gives the following formal profiles and their costs:Thus choice (3) is the best strategy, and its true minimum cost isThe qualification from part (b) applies to row (1): its formal quadratic is not a minimizer with free terminal speed, since . Row (2) is a genuine minimizer for its fixed zero terminal speed, and row (3) is the genuine free-terminal-speed minimizer, satisfying its natural condition .
A direct lower bound makes the comparison rigorous. For every admissible speed with ,by integration by parts. The Cauchy-Schwarz inequality gives . Equality requires to be proportional to , giving exactly row (3). Row (1)'s zero initial acceleration excludes equality; however short initial layers, as in part (b), approach that same infimum. Hence choice (1) has infimum but does not attain it, while choice (3) does. This distinction resolves the boundary-condition issue in the printed minimization request.
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